Mechanical Engineer's Handbook

Fluids, Density, and Pressure

A fluid is any state of matter that flows and yields to shearing (sideways) forces rather than resisting them. Both liquids and gases are fluids:

  • Liquids: Definite volume, nearly incompressible, atoms in close contact but free to slide.
  • Gases: Variable volume, highly compressible, large separation between atoms.

Density and Specific Gravity

Average density (ρ\rho) is defined as mass per unit volume:

ρ=mV\rho = \frac{m}{V}
(1)

In heterogeneous materials where density varies throughout the volume, local density at a point is defined by taking the limit:

ρ=limΔV0ΔmΔV=dmdV\rho = \lim_{\Delta V \to 0} \frac{\Delta m}{\Delta V} = \frac{dm}{dV}
(2)
  • SI Unit: kg/m3\text{kg/m}^3 (1 g/cm3=1000 kg/m31 \text{ g/cm}^3 = 1000 \text{ kg/m}^3).
  • Water Standard: ρwater=1000 kg/m3\rho_{\text{water}} = 1000 \text{ kg/m}^3 at 4.0C4.0^\circ\text{C}.

Specific Gravity is a dimensionless ratio comparing a material's density to the density of water at 4.0C4.0^\circ\text{C}:

Specific Gravity=ρmaterialρwater\text{Specific Gravity} = \frac{\rho_{\text{material}}}{\rho_{\text{water}}}
(3)

Pressure

Average pressure (pp) is the perpendicular force per unit area:

p=FAp = \frac{F_{\perp}}{A}
(4)

For non-uniform forces or infinitesimal surfaces, local pressure at a point is given by:

p=dFdAp = \frac{dF_{\perp}}{dA}
(5)
  • SI Unit: Pascal (1 Pa=1 N/m21 \text{ Pa} = 1 \text{ N/m}^2).
  • Standard Atmosphere: 1 atm=1.013105 Pa=101.3 kPa1 \text{ atm} = 1.013 \cdot 10^5 \text{ Pa} = 101.3 \text{ kPa}.

Pressure is a scalar quantity that acts equally in all directions at a point within a fluid; the force exerted by pressure always acts perpendicularly to any surface it contacts.

Example 1

A solid metal sphere of radius r=2.0 cmr = 2.0 \text{ cm} has a mass of 0.28 kg0.28 \text{ kg}. Calculate its average density and its specific gravity.

Use the volume of a sphere V=43πr3V = \frac{4}{3}\pi r^3 to find density, then divide by ρwater=1000 kg/m3\rho_{\text{water}} = 1000 \text{ kg/m}^3.

First, convert radius to meters (r=0.020 mr = 0.020 \text{ m}) and calculate volume:

V=43πr3=43π(0.020 m)33.35105 m3V = \frac{4}{3}\pi r^3 = \frac{4}{3}\pi (0.020 \text{ m})^3 \approx 3.35 \cdot 10^{-5} \text{ m}^3

Calculate average density using Equation 1:

ρ=mV=0.28 kg3.35105 m38360 kg/m3\rho = \frac{m}{V} = \frac{0.28 \text{ kg}}{3.35 \cdot 10^{-5} \text{ m}^3} \approx 8360 \text{ kg/m}^3

Calculate specific gravity using Equation 3:

Specific Gravity=8360 kg/m31000 kg/m3=8.36\text{Specific Gravity} = \frac{8360 \text{ kg/m}^3}{1000 \text{ kg/m}^3} = 8.36